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how to book reliance jio mobile phone for free

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Reliance Jio announced the launch of the Jio Phone at the annual Reliance Industries AGM on Friday. The effective price of the phone is zero - you need to pay a Rs. 1,500 deposit up front, which is refundable after three years. Jio Phone users can enjoy Reliance Jio services like free voice calling and SMS, as well as access to Jio apps like JioTV and JioMovies at Rs. 153 per month, Reliance Industries Chairman Mukesh Ambani said. This Jio plan also gets you 'unlimited' Internet data, with a daily high-speed data cap of 500MB. So is the Jio Phone going to be the phone that gets the next set of Indians on the Internet? What are its limitations? Does the Jio Phone run WhatsApp? Read on for the answers to these, and other questions. Jio Phone launch date and booking The Jio Phone will be made available starting August 15 in a beta programme, and it will be up for pre-booking from August 24 onwards. Pre-orders can be made using the MyJio app or Jio offline stores. Customers who pre
SSC Recruitment 2017 – Apply Online for Stenographer Grade C & D Exam:  Staff Selection Commission (SSC) has announced a notification to conduct Stenographer Grade C & D Examination 2017 for the recruitment of Stenographer vacancies. Eligible candidates may apply online from 17-06-2017 to 15-07-2017 up to 05:00 P.M. Other details like age limit, educational qualification, selection process, application fee & how to apply are given below… SSC Vacancy Details: Name of the Exam: Stenographer Grade C & D Examination 2017 Name of the Post: Stenographer Age Limit:  Candidates age should be 18-27 years as on 01-08-2017. Age relaxation is applicable as per rules. Educational Qualification:  Candidates should have passed 12th Standard or equivalent from a recognized Board or University. Selection Process:  Candidates will be selected based on computer based written exam & skill test in stenography. Application Fee:  Candidates should pay Rs. 100/- through SBI Challan/ SBI Ne

SSC Recruitment 2017-1102 Scientific Assistant Posts

SSC Recruitment 2017 – Apply Online for 1102 Scientific Assistant Posts:  Staff Selection Commission (SSC) has advertised a notification for the recruitment of Scientific Assistant in India Meteorological Department, Group B, Non-Gazetted, Non-Ministerial vacancies on regular basis. Eligible candidates can apply online from 18-07-2017 to 04-08-2017 upto 05:00 p.m. Other details like age limit, educational qualification, selection process, application fee & how to apply are given below… SSC Vacancy Details: Total No. of Posts: 1102 Name of the Post: Scientific Assistant Age Limit:  Candidates age limit should be not exceeding 30 years as on 04-08-2017. Age relaxation is admisssible as per rules. Educational Qualification : Candidates should possess Bachelor’s Degree in Science (with Physics as one of the subject)/ Computer Science/Information Technology/ Computer Applications or Diploma in Electronics and Telecommunication Engineering from a recognized Institution/ University or equ

Time and speed

Welcome to aptitude tricks Problems involving Time, Distance and Speed are solved based on one simple formula. Distance = Speed * Time Which implies → Speed = Distance / Time   and Time = Distance / Speed Let us take a look at some simple examples of distance, time and speed problems. Example 1.  A boy walks at a speed of 4 kmph. How much time does he take to walk a distance of 20 km? Solution Time = Distance / speed = 20/4 = 5 hours. Example 2.  A cyclist covers a distance of 15 miles in 2 hours. Calculate his speed. Solution Speed = Distance/time = 15/2 = 7.5 miles per hour. Example 3.  A car takes 4 hours to cover a distance, if it travels at a speed of 40 mph. What should be its speed to cover the same distance in 1.5 hours? Solution Distance covered = 4*40 = 160 miles Speed required to cover the same distance in 1.5 hours = 160/1.5 = 106.66 mph Now, take a look at the following example: Example 4.  If a person walks at 4 mph, he covers a certain distance. If he walks at 9 mph, he

Examples of time and work

Welcome to aptitude tricks 27) A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in: a) 5 days b) 6 days c) 10 days d) 10 e) None of these 28) X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work? a) 13 b) 15 days c) 20 days d) 26 days e) None of these 29) A and B can do a job together in 7 days. A is 1 times as efficient as B. The same job can be done by A alone in: a) 9 b) 11 days c) 12 d) 16 e) None of these 30) P is thrice as efficient as Q and is therefore able to finish a piece of work in 60 days less than Q. Find the time in which P and Q can complete the work individually. a) 90 days, 30 days b) 60 days, 20 days c) 65 days, 30 days d) 85 days, 90 days e) None of these 31) A tub can be filled in 20 minutes but there is a leakage in it which can empty the full tub in 60 minutes.

Examples of time and work 10

Welcome to aptitude tricks 17) A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days? a) 11 days b) 13 days c) 20 d) Data inadequate e) None of these 18) Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages? a) 7 hours 30 minutes b) 8 hours c) 8 hours 15 minutes d) 8 hours 25 minutes e) None of these 19) A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in: a) day b) day c) 3 ] d) 4 days e) None of these 20) Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is: a) 15 b) 16 c) 18 d) 25 e) None of these 21) A takes twice as much time as B or t

Examples of time and work

Welcome to aptitude tricks Exercise - 12 1) A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is: a) 1/4 b) 1/10 c) 7/15 d) 8/15 e) None of these 2) A can lay railway track between two given stations in 16 days and B can do the same job in 12 days, with help of C, they did the job in 4 days only. Then, C alone can do the job in: a) 9 b) 9 c) 9 d) 10 e) None of these 3) A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day? a) 12 days b) 15 days c) 16 days d) 18 days e) None of these 4) A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in: a) 20 days b) 22 c) 25 days d) 30 days e) None of these 5) A alone can do a piece of work in 6 days and B alone 8 days. A and B undertook to do it for Rs.3200. With the help of C, they completed th

Time and work 9

Welcome to aptitude tricks Question 2 - A is twice as efficient as B and can complete a job 30 days before B. In how much they can complete the job together? Solution - Let efficiency percentage as x A's efficiency = 2x and B's efficiency = x A is twice efficient and can complete the job 30 days before B. So, A can complete the job in 30 days and B can complete the job in 60 days A's efficiency = 1/30 = 3.33% B's efficiency = 1/60 = 1.66% Both can do 5% (3.33% + 1.66%) of the job in 1 day. So the can complete the whole job in 20 days (100/5) Question 3 - A tank can be filled in 20 minutes. There is a leakage which can empty it in 60 minutes. In how many minutes tank can be filled? Solution - Method 1 ⇒ Efficiency of filling pipe = 20 minutes = 1/3 hour = 300% ⇒ Efficiency of leakage = 60 minutes = 100% We need to deduct efficiency of leakage so final efficiency is 200%. We are taking 100% = 1 Hour as base so answer is 30 minutes. Method 2 ⇒ Efficiency of filling pipe =

Time and work 7

Welcome to aptitude tricks Example 2: If a person can complete his work in 5days. What will be his efficiency? Solution: Number of days a person take to complete his work = 5 ⇒ He is doing 1/5 th work per day (converted into fraction) Convert it into percentage: 100/5 = 20% Therefore, his efficiency is 20%. Summarizing, If a person can do his job in n days, efficiency will be Efficiency = % Note: Negative efficiency cancels the positive efficiency For Example: Positive efficiency = 5% Negative efficiency = 1.5% Net efficiency = 5- 1.5 = 3.5% As we all know, in competitive exams time management is very important. I suggest you to learn the fractions till 15. Number of days required to complete work Work/Day Efficiency (%) N 1/n 100/n 1 1 100 2 1/2 50 3 1/3 33.33 4 1/4 25 5 1/5 20 6 1/6 16.66 7 1/7 14.28 8 1/8 12.5 9 1/9 11.11 10 1/10 10 11 1/11 9.09 12 1/12 8.25 13 1/13 7.69 14 1/14 7.14 15 1/15 6.66 Example 3: A can do a job in 10 days. B can do a job in 5 days. In how many days they c

Time and work

Welcome to aptitude tricks Chapter - 12 Time and Work Three main factors of Time and Work There is a definite relationship between Time and Work. In this concept, there are only three factors:  Time taken to complete a certain job  Unit of work done  Number of persons doing the job There is a mental relationship between these three, discussed as follows: Work done (W) = Number of days (Time taken) (T or D) × Number of men (M) W = D × M Some basic points More number of men can do more work i.e. both are directly proportional More number of men take less time to complete certain job i.e. both are inversely proportional By summarizing, we get = × Let us start solving some examples: Example 1: 10 men can cut 8 trees in 16 days. In how many days can 6 men cut 10 trees? Solution: This is a very simple example. You are given: W1 = 8 W2 = 10 M1 = 10 M2 = 6 D1 = 16 D2 = ? Using formula, = × = × ⇒D2 = 33.3 Concept of efficiency This means, "How much work one person can do in one day (exp

Clock 1

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Welcome to aptitude tricks Basic Concepts & Short Tricks to solve Clock related Questions in Reasoning The Reasoning section of every competitive exam includes questions from the topic “Clock”. This topic is considered to be quiet important and every year a good number of questions are asked from this topic. We are providing you with Basic Concepts & Short Tricks to solve Clock related Questions in Reasoning which will surely help you in the upcoming SSC Exams 2016. Clock A clock is an instrument used for indicating and maintaining the time. It is an electronic device that present the duration of hour, minute and second. Different types of question  covered in this chapter are as follows. Angle Between the Hands of clock Position of Hands of clock Faulty clocks Time Gained or lost by clock The clock represents two things. i.e., minutes and hour. The minute is a unit of time equal to 1/60 th  of an hour or 60 s i.r., 1 min = 60 s. Clocks Concepts : The dial of the clock is circu

Calendar 1

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Welcome to aptitude tricks In order to solve these type of problems you must know some codes. Year Code Month Code Day Code Year Code:- 1600-1699 6 1700-1799 4 1800-1899 2 1900-1999 0 2000-2099 6  Month Code:- Jan Feb Mar April May June July Aug Sep Oct Nov Dec 0 3 3 6 1 4 6 2 5 0 3 5  Day Code:- Sunday Monday Tuesday Wednesday Thursday Friday Saturday 0 1 2 3 4 5 6 Steps to solve:- Step 1:  Add the day digit to last two digit of the year. Step 2:   Divide the last two digits of the year by four. Step 3:   Add the Quotient value in step 3 to result obtain in  step 1 . Step 4:   Add Month Code and year codes to the result obtain in  step3 . Step 5:   Divide the result of  step4  by seven. Step 6:  Obtain the remainder and match with the day code. Example:-

Simplification 4

Welcome to aptitude tricks Hello Aspirants. Welcome to Online  Quantitative Aptitude  Section with explanation in AffairsCloud.com. Here we are creating question sample in  Simplification.  We have included Some questions that are repeatedly asked in bank exams !!! 572 ÷ 26 x 12 – 200 = 2 ?   A. 5 B. 3 C. 6 D. 7 E. None of these Answer & Explanation Answer –  C. 6 Explanation : 572 ÷ 26 = 22 22 x 12 = 264 264 – 200 = 64 = 2 6 43931.03 ÷ 2011.02 x 401.04 = ? A. 7500 B. 8300 C. 8800 D. 8850 E. None of these Answer & Explanation Answer –  C. 8800 Explanation : (44000  ÷  2000) x 400 = 8800 [(3√8 + √8) x (8√8 + 7√8)] – 98 = ? A. 352 B. 382 C. 362 D. 372 E. None of these Answer & Explanation Answer –  B. 382 Explanation : [√8(3 + 1) x √8(8 + 7)] – 98 [4√8 x 15√8] – 98 480 – 98 = 382 (23.1) 2  + (48.6) 2  – (39.8) 2  = ? + 1147.69 A. 185.84 B. 175.84 C. 135.84 D. 163.84 E. None of these Answer & Explanation Answer –  D. 163.84 Explanation : 533.61 + 2361.96 – 1584.04 = ? + 11